Defining a function (including vector dot product) for all the points in 3D
2 views (last 30 days)
Show older comments
I am trying to build the following function in a three dimensional domain.
where k is a constant vector, X is the position vector, c is a constant number, and t is time.
k is a vector of size [1 3], X is an array of size [NX*NY*NZ 3] that represents the points in the three-dimensional domain, c is a constant, and t is an array of size [1 NT].
The following is the setup of the problem.
dx = 0.1;
dy = 0.5;
dz = 0.1;
[x, y, z] = meshgrid( (1:100)*dx, (1:100)*dy, (1:100)*dz );
X = [x(:) y(:) z(:)];
k = [1 2 3];
c = 0.5;
t = 0:0.1:1;
I thought about using arrayfun and repeating the vector k using repmat and dot it with X in the second dimension but I don't know what I should do for the multiplication of c and t.
In fact, the following loop works but it is very slow (takes 200 seconds on my machine).
f = zeros(numel(X)/3, numel(t));
for n = 1:numel(t)
for i = 1:numel(X)/3
f(i, n) = tan(dot(k, X(i,:)+c*t(n)));
end
end
What would be an efficient way of defining the function for all the points and all the times? The output of this function, for example, looks like an array of size [NX*NY*NZ NT].
1 Comment
Accepted Answer
Matt J
on 3 Jun 2014
f = tan( bsxfun(@plus, X*k(:), c*t) );
3 Comments
Matt J
on 3 Jun 2014
This is probably a bit faster
k = [1 2 3];
c = 0.5;
t = 0:0.1:1;
[x, y, z] = meshgrid( (1:100)*(k(1)*dx),
(1:100)*(k(2)*dy),
(1:100)*(k(3)*dz);
f=tan( bsxfun(@plus, x(:)+y(:)+z(:), ct) );
More Answers (1)
George Papazafeiropoulos
on 3 Jun 2014
Edited: George Papazafeiropoulos
on 3 Jun 2014
% data
dx = 0.1;
dy = 0.5;
dz = 0.1;
[x, y, z] = meshgrid( (1:100)*dx, (1:100)*dy, (1:100)*dz );
X = [x(:) y(:) z(:)];
k = [1 2 3];
c = 0.5;
t = 0:0.1:1;
lt=length(t);
% engine
u=numel(X)/3;
t=t(ones(u,1),:);
X=repmat(X,lt,1);
t=t(:);
t=t(:,ones(1,3));
u1=sum(k(ones(numel(X)/3,1),:).*(X+c*t),2);
ff=tan(u1);
% result
ff=reshape(ff,u,[])
0 Comments
See Also
Categories
Find more on Matrices and Arrays in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!