How can I find the largest number

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Hi, I have 3 numbers and I have to find the biggest one, what is the best way? This is the code:
T=200
if isempty(counter) || counter >= T
counter=0;
d1=0.1
d2=0.2
d3=0.6
else counter=counter+1
if counter>0
if d1=max([d1,d2,d3)]
...
elseif d2=max([d1,d2,d3)]
...
elseif d3=max([d1,d2,d3)]
...
end
end
end
But this code doesn't work, thank you
  3 Comments
alessandro
alessandro on 2 Jul 2014
I just need to know which is the greater one in order to define another variable, for example:
if d1=max([d1,d2,d3)]
V=V1
elseif d2=max([d1,d2,d3)]
V=V1
elseif
...
Roberto Calandra
Roberto Calandra on 2 Jul 2014
Remember that with d1=max([d1,d2,d3]) you are assigning a variable to d1but what you want is checking for equality as in d1==max([d1,d2,d3])

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Accepted Answer

Elias Gule
Elias Gule on 2 Jul 2014
numbers = [num1 num2 num3]; % the array of numbers from which to search
maxVal = max(numbers); % the highest number

More Answers (3)

Roberto Calandra
Roberto Calandra on 2 Jul 2014
Something like this?
switch max([d1,d2,d3])
case {d1}
V=V1
case {d2}
V=V2
case {d3}
V=V3
end

Robert Cumming
Robert Cumming on 2 Jul 2014
you need to use
==
for comparison, i.e.
if d1==max([d1,d2,d3)]
etc...

b.lokendra sri sai
b.lokendra sri sai on 9 Jan 2021
T=200
if isempty(counter) || counter >= T
counter=0;
d1=0.1
d2=0.2
d3=0.6
else counter=counter+1
if counter>0
if d1=max([d1,d2,d3)]
...
elseif d2=max([d1,d2,d3)]
...
elseif d3=max([d1,d2,d3)]
...
end
end
end

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