Error using length, Too many input arguments.

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I have a bunch of data from animal cells at different times. j represents the time frame. I want to extract a field from my object and that field can either have one or two values. If I have one value, I want to extract the value as it is and if I have two values, I want to average them out. This is a snippet of my code.
if length(Obj.MatFile{cellnumber}{j},ExtractField)==2
Answer(icellnumber,i)=mean(Obj.MatFile{cellnumber}{j}.(ExtractField));
else
Answer(icellnumber,i)=Obj.MatFile{cellnumber}{j}.(ExtractField);
end
I keep getting the above error. Any help would be greatly appreciated. Thanks in advance.

Accepted Answer

Matt J
Matt J on 30 Aug 2021
Edited: Matt J on 30 Aug 2021
The first line shouldn't have any commas.
  3 Comments
Matt J
Matt J on 31 Aug 2021
Ina later line of the code, you have
Obj.MatFile{cellnumber}{j}.(ExtractField)
Shouldn't it be referenced that way everywhere else, too?

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More Answers (1)

Stephen23
Stephen23 on 31 Aug 2021
Edited: Stephen23 on 31 Aug 2021
if length(Obj.MatFile{cellnumber}{j}.(ExtractField))==2
But note that you do not need to check the length: taking the mean of one value simply returns that value, so in both cases you can simply do this (and not worry about how many values there are):
Answer(icellnumber,i) = mean(Obj.MatFile{cellnumber}{j}.(ExtractField));
and then get rid of the IF entirely.
  2 Comments
C A
C A on 31 Aug 2021
Thank you. This is the most sensible way to do this. I just wanted to learn how to use 'length' function because I need to remove values if there are more than two.
Walter Roberson
Walter Roberson on 1 Sep 2021
"if there are more than two" -- use numel() instead of length() if you want to know how many values there are. length() has a slightly different meaning.

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