Permutation of specific strings in switch cases and test on what is put in locations (the strings)

I have called this post for permutation in switch, but I am not sure that it was the right title for the question.

I have three strings such as:

A='abcdh' ;
B='efghn';
C='ijklm ';

I have also a matrix of permutated '123' such as U = perms('123');

I run to a for-loop to test all U's

and in that for-loop for each element in U, I need to do something

something is:

I need to for the first element of U, say it is '321',

put A,B,C in three different locations.

like

location1 = A;
location2 = B;
location3 = C;

and then I need to do a test with what is in these locations, after the test then I need to change what I put in these locations like:

location1 = B;
location2 = C;
location3 = A;

and again do all tests on what is in these locations.

and then after that change what I put in these locations again, do this until all

'CBA'

'CAB'

'BCA'

'BAC'

'ACB'

'ABC'

have participated in the test. After that then I need to do the whole round with the next element in the U matrix.

'321'

'312'

'231'

'213'

'132'

'123'

Say the test is done with '321' then do all that with '312' etc.

I could guess that I should start with a switch such as: (or a for-loop could be better? i guess)

switch U
    case ...%the first element of U
%put A,B,C in new locations
%do the test on what is put (those strings) in those locations
% test the next element in U matrix I guess by going to the next case
    case 
        ...
end

*The test shall be done on the strings which are defined in the first place.

But some how I need help to set this up

any idea would be appriciated.

[Lawrence]

With a switch statement, you only get to run one case. And it's the entire U (not each row) that gets tested against the cases when choosing which one to run.

Answer 1

[Lawrence]

I'd do this with nested for loops, using perms() a second time to go through the locations:

A='abcdh';
B='efghn';
C='ijklm';

U = perms('123');
locations = perms({A B C})

for i = 1:size(U,1)
    for j = 1:size(locations,1)
        u = U(i,:);
        location1 = locations{j,1};
        location2 = locations{j,2};
        location3 = locations{j,3};
        
        %Perform test here
    end
end

[Nicle Davidson]

I think this code should work, please let me test, it will take a bit time, but I think this will work, I will come back here and click on accept when tested, and yes, the test will run the same test code. And yes for loop is suited better I see for this case. I will come back and click on accepted when I test it. I appreciate your time and effort.