New variable based on a 'percentile' condition

I have a double variable A with 6000 rows and 3 columns:

• C1 gives the year;
• C2 gives a code (no repetitions within each year);
• C3 gives a number;

     C1         C2      C3
  A=[1983  11  54
     1983  13  24
     1983  16  32
     1983  20  11
     1983  25  14
     1983  28  23
     1983  29  19]

B, is a cell variable with 1 row and 31 columns (each column corresponds to a year) that gives the 90th percentile of A(:,3) per year:

B={53  49.3  51.7  49.2  48  40  41  44.6  …}

I am trying to obtain a new variable A2 that would be equal to A, but would only consider the cases in which A(:,3) > B(1,:).

For example, I have already done something similar but with different conditions, only in these cases my condition would not change from year to year:

numMean=A(A(:,3)>=42.8,[1 2 3]);
num25=A(A(:,3)>=25,[1 2 3]);

Thank you very much for your help.

[Azzi Abdelmalek]

The condition A(:,3) > B(1,:) is not clear

Answer 1

[Azzi Abdelmalek]

 B={53  49.3  51.7  49.2  48  40  41}
A=[1983  11  54
     1983  13  24
     1983  16  32
     1983  20  11
     1983  25  14
     1983  28  23
     1983  29  19]
 out=A(all(bsxfun(@gt, A(:,3),cell2mat(B)),2),:)

Answer 2

[Kelly Kearney]

Could do it all it one step with accumarray. Though this way doesn't preserve the initial order... not sure if that is necessary or not for your task.

% Fake data

n = 100;
A = [floor(rand(n,1)*5) + 1983 ones(n,1) round(rand(n,1)*100)];

% Find values >90% of their year

[unqyr, blah, ia] = unique(A(:,1));
nyr = length(unqyr);

atop = accumarray(ia, A(:,3), [nyr 1], @(x) {x(x > prctile(x,90))});
cell2mat(atop)