Filling a 3d matrix from columns

say we create a empty 3d matrix

    A= zeros(30,30,361)

I have variable Pix, a 361 x 12 double matrix, were each column is the length of 361 data point. There are 12 samples columns, How would i randomly grab each column sample and fill the zeros matrix "A" so that all 361 data points in the 12 column lay on the matrix in 1 x 1 x 361 until it has filled all 30 x 30 positions.

Answer 1

[Joseph Cheng]

so you can use randi(12,30,30) to generate a 30x30 matrix of values 1 to 12 to select which of the 12 columns to place in the row/column location. then use for loops to go through each index and specify the column.

example:

x = rand(361,12);
randcolumn = randi(12,30,30);

A = zeros(30,30,361);

for ind = 1:30
    for jnd = 1:30
    A(ind,jnd,:) = x(randcolumn(ind,jnd));
    end
end

[Arjun Raja]

Kind of late but is there any way to do this without using a for loop?