Index exceeds the number of array elements (1). How can I correct this error?

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Hi I've got this code that gives me the messages from a variable that are from a mmsi that I want
Msg_mmsi_selected = [];
for i=1:1:L
seq1 = msg_NoMatchAIS1(i);
linia=convertStringsToChars(seq1);
if linia(13)=='A' && linia(15)=='1'
sequencia = ais_to_bit(linia(15:44));
s_mmsi=sequencia(9:38);
mmsi= bin2dec(num2str(s_mmsi));
Msg_mmsi_selected = seq1(mmsi_selected); % Here is the line that give me error
end
end
and the error I got is
Index exceeds the number of array elements (1).
Is there any problem in the line code that makes me this error. I thought it was because of not named the variable but I did and do not know why I continue having it.
  3 Comments
flashpode
flashpode on 26 Oct 2021
well I am gonna changa the question due to a change of code. That maybe it is easy for me to explain. Lets see, I've got a variable that is num_mmsi_selected that has the number of the mmsi in the position that we find it. So my question is how can I change the number of the mmsi to the number of the cell with find it. Now a example:
Here we can see that in the cells 5 and 6 there is the mmsi so I want to change this number and put 5 and 6 the same with all the lines that have this number. I uploaded the data so you can work easily.

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