How to give IF condition in following code?

I have following code. It is generating some random values of y (0 or 1). I want it to select at least 2 ones's(1) and it it should never select all zeros (0).

for i=1:W
  y = randi([0 1]);
  QTWM2 = round(((1000-500)*(rand(1)))+500);
  WSCT= y* round(((1500-1000)*(rand(1)))+1000);
  WCST1(i)=WSCT;
  QTWM1(i)=QTWM2;
  f11(i) = y;
  f1(i)=CFWT*y;
end

Please provide me with the solution

[Joachim Schlosser]

What have you tried so far for conditions?

[Abhinav]

Sorry Sir, I didn't get you. Please make yourself more clear.

[Michael Haderlein]

Actually, it's difficult to understand the question itself. Your code creates a bunch of random values, between 500 and 1000 (QTWM), between 1000 and 1500 plus 0 (WSCT), either 0 or 1 (f11) and either 0 or CFWT (f1). So what is now the question? Out of which array(s) should the values be chosen? How many values should be chosen?

[Abhinav]

In this code 'y' will generate an array depending upon the value of 'W'. Let W = 5 so it will generate an array of 0 & 1 for 5 places. Suppose it generates [0 0 0 1 1]. I want that whatever the value of W it should only execute the loop if it has at least 2 ones in it. For eg for W=6 [0 0 0 0 0 1] is unacceptable but [0 0 0 0 1 1] is acceptable. I have no concern with other values. If it satisfies the condition only then it should display result to me otherwise run again

Answer 1

[Roger Stafford]

   b = true;
   while b
     yt = randi([0,1],W,1);
     b = (sum(yt)<2); % Repeat if 'yt' has less than two ones
   end
   for i=1:W
     y = yt(i);
     QTWM2 = ....
     ....

The while-loop will seldom have to repeat itself.