How to convert a Ascii Text input to Binary Output

Hi, i am given an ASCII value as an input and i want to convert it into BINARY Output.

[G F]

Hello Guys,could you tel me the meaning of this command line:-

function rem = binary_rem(input, genpol)

input = [input zeros(1,length(genpol)-1) 0];

Answer 1

[Star Strider]

Your question is a bit ambiguous, but this may be what you’re looking for:

asv = uint8('A')
asb = dec2bin(asv)

produces:

asv =

     65

asb =

1000001

[G F]

shall i also use this...:-

msg=str2num(msg)

so that i can also give a loop for "msg"...

[G F]

Hello Guys,could you tel me the meaning of this command line:-

function rem = binary_rem(input, genpol)

input = [input zeros(1,length(genpol)-1) 0];

[Star Strider]

First, str2num converts a number represented as a string into a double-precision number, so:

q = str2num('A')

returns:

q =

       []

which is probably not what you want.

This line:

r = uint8('AaBbQqZz')

produces:

r =

     65   97   66   98   81  113   90  122

that probably is what you want.

Second, the ‘binary_rem’ function takes the (badly-named) ‘input’ variable and concatenates a vector of zeros to the end of it. I have no idea what its purpose is in the script that calls it. (Note that input is a built-in MATLAB function. It is not a good idea to name a variable the same as a function, but here you can get away with it because it is local to the ‘binary_rem’ function only.)

[G F]

yes.perfect...!!!

Thanks.

[G F]

But then what is the difference between uint8('') and uint32('')..??

[G F]

ok i got it it is just the difference that it converts into 32 and 8 bit unsigned integer.

[Star Strider]

Correct. The difference is the number of bits used. For ASCII encoding, eight is enough.

[G F]

Yes thanks again... :)

[Star Strider]

My pleasure!