if loop on array

19 views (last 30 days)
ali hassan
ali hassan on 7 Feb 2022
Commented: Image Analyst on 11 Feb 2022
i want to use if loop on a array. let say if i have two arrays:
a=[1 2 3 4 5]
b=[2 3 4 5 6]
now if i want to use if loop such that when any value in array 'a' is 3 and corresponding value in array 'b' is 4,it should print 'ali'.
i tried the following code but it did'nt work.
a=[3 4 3 44 3];
b=[4 3 4 34 26];
if (any(a==3) & b==4)
sprintf('ali')
end

Accepted Answer

Image Analyst
Image Analyst on 10 Feb 2022
Your parentheses are not right. Try it this way
a=[3 4 3 44 3];
b=[4 3 4 34 26];
if any(a==3 & b==4)
fprintf('ali\n')
end
ali
A=[1 2 5 66 7];
B=[6 4 4 77 8];
% if any element in array A is 5 and the corresponding B element is between 2 and 6
if any(A==5 & B>=2 & B<=6)
fprintf('ali')
else
fprintf('No Matches.\n')
end
ali
  5 Comments
ali hassan
ali hassan on 11 Feb 2022
here we have a vector column 'FF_liter_ho_'.If i want to know that how many times non zero values were greater than 770 in a row.
so it happened only once in the column.
Image Analyst
Image Analyst on 11 Feb 2022
@ali hassan if you have the Image Processing Toolbox, you can use regionprops():
ff_liter_ho = [nan, 75, 0, nan, nan, nan, nan, nan, nan, nan, 75, 37, nan, 0, 1, 2, 3, 4]
ff_liter_ho = 1×18
NaN 75 0 NaN NaN NaN NaN NaN NaN NaN 75 37 NaN 0 1 2 3 4
nonZeroIndexes = ff_liter_ho > 0
nonZeroIndexes = 1×18 logical array
0 1 0 0 0 0 0 0 0 0 1 1 0 0 1 1 1 1
props = regionprops(nonZeroIndexes, 'Area');
numRuns = length(props)
numRuns = 3
runLengths = [props.Area]
runLengths = 1×3
1 2 4

Sign in to comment.

More Answers (1)

KSSV
KSSV on 7 Feb 2022
a=[3 4 3 44 3];
b=[4 3 4 34 26];
if (any(a==3))
idx = a == 3 ;
if any(b(idx) == 4 )
fprintf('ali\n')
end
end
  4 Comments
ali hassan
ali hassan on 10 Feb 2022
assume, i have an array
A=[1 2 5 66 7] and B=[6 4 4 77 8]
i want to put if condition such that if any element in array A is 5 and the corresponding is between 2 and 6, i want to know how many times the condition meets.

Sign in to comment.

Categories

Find more on MATLAB in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!