# Why am i getting length(x) as 11 instead of 16?

1 view (last 30 days)
john on 13 Mar 2022
Answered: Image Analyst on 13 Mar 2022
n=0:15;
Walter Roberson on 13 Mar 2022
x and x1 are not the same

Torsten on 13 Mar 2022
If you display
length(x1)

Image Analyst on 13 Mar 2022
What did you define for x? All we see are definitions for n and x1:
n=0:15;
% Compute x1
x1 = 1 .* (n >= 1) & (n <= 10)
x1 = 1×16 logical array
0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0
x1Length = length(x1) % Display it's length.
x1Length = 16
% Now define some x - a different variable than x1
x = [1,2,3,4] % Or whatever it might be.
x = 1×4
1 2 3 4
xLength = length(x) % Display it's length.
xLength = 4
I bet you had an x hanging around from a prior run and didn't call "clear all" so when you did length(x) you were getting some x that was still in the base workspace even though it was not in your script. Calling clear all would clear all old variables and prevent a problem like that.

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