Why am i getting length(x) as 11 instead of 16?

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john
john on 13 Mar 2022
Answered: Image Analyst on 13 Mar 2022
n=0:15;

Answers (2)

Torsten
Torsten on 13 Mar 2022
If you display
length(x1)
the answer should be 16.

Image Analyst
Image Analyst on 13 Mar 2022
What did you define for x? All we see are definitions for n and x1:
n=0:15;
% Compute x1
x1 = 1 .* (n >= 1) & (n <= 10)
x1 = 1×16 logical array
0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0
x1Length = length(x1) % Display it's length.
x1Length = 16
% Now define some x - a different variable than x1
x = [1,2,3,4] % Or whatever it might be.
x = 1×4
1 2 3 4
xLength = length(x) % Display it's length.
xLength = 4
I bet you had an x hanging around from a prior run and didn't call "clear all" so when you did length(x) you were getting some x that was still in the base workspace even though it was not in your script. Calling clear all would clear all old variables and prevent a problem like that.

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