imrotate3 gives me just zeros with 'linear'

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Mads
Mads on 7 Jun 2022
Edited: DGM on 10 Jun 2022
For imrotate3() the doc says:
"'linear' Trilinear interpolation. Trilinear interpolation is the default method for numeric and logical images."
Now if I have a 3D mask of zeros and ones... let's call it BW and it is of type logical, and I use
BW2 = imrotate3(BW,45,[0 0 1],'linear','crop');
Then BW2 is all zeros.
If I convert to, say, double or single, it works as expected.
Or if I use 'nearest' instead of 'linear', it works with logical.

Accepted Answer

Jan
Jan on 7 Jun 2022
Edited: Jan on 7 Jun 2022
I cannot confirm this, but it is even stranger:
BW = rand(5, 5, 5) > 0.5;
BW2 = imrotate3(BW, 45, [0, 1, 0], 'linear', 'crop');
BW3 = 5×5×5 logical array
BW3(:,:,1) = 204 160 0 0 158 59 230 0 204 160 127 63 0 59 230 102 0 0 127 63 158 0 0 102 105 BW3(:,:,2) = 179 243 0 0 0 125 191 0 0 240 51 0 0 0 63 219 0 0 0 0 225 0 0 0 0 BW3(:,:,3) = 0 0 0 59 230 0 0 0 127 191 0 0 0 102 0 0 0 0 158 0 0 0 203 160 0 BW3(:,:,4) = 0 206 160 255 64 0 59 230 255 0 0 127 63 255 0 0 102 254 255 0 128 158 255 7 0 BW3(:,:,5) = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
ans =
ans(:,:,1) = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ans(:,:,2) = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ans(:,:,3) = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ans(:,:,4) = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ans(:,:,5) = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
I;
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  3 Comments
DGM
DGM on 10 Jun 2022
Edited: DGM on 10 Jun 2022
If it was in R2019b, I'm going to guess it was present when imrotate3() was released -- R2017a. The IPT release notes don't mention any changes to it until R2020a, and there are no bug reports. Then again, the release notes aren't comprehensive and there are plenty of significant bugs that never get put in the publicly listed bug reports.

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