How to find euclidean distances of each column of the two matrices?

I have two matrices X and Y, of order 5*3 order

I want to find euclidean distance of 1st column of X matrix and 1st column of Y matrix. Subsequently for 2nd and 3rd column of X and Y matrix.

The solution should be in 1*3 order. How can we proceed this problem?

pdist2(xySet1, xySet2); This solution is for solving eucliden distance of each row of X and Y.

I want to find their distances of each column of the two matrices but I can't understand the help page on pdist.

[Rik]

So you have 15 points, and you want to calculate the distances between groups of 5 points, but for each group you only want to store 1 value. What value would that be?

[chan]

A= 0.5958 0.8909 0.9135

0.5348 0.0558 0.4093

0.0265 0.1159 0.8576

0.0066 0.1568 0.8366

0.4693 0.2467 0.2841

B= 0.4251 0.2552 0.8203

0.3655 0.3306 0.3039

0.4244 0.4263 0.1493

0.4422 0.3184 0.2394

0.0107 0.1467 0.8425

i want to find distance between 1st column of A matrix and 1st column of Y matrix which leads to one single value as solution. similarly for 2nd and 3rd column by applying eucliden distance

After calculating we should get 3 values.

C=[x y z]

How can we proceed this?

[Rik]

I don't understand what you expect to happen, so I hope the solutions below will help.

For 5 pairs of x and y you expect a single distance. What is the distance between 5 points? The solutions below assume you want the sum of the 4 subsequent distances. Do you?

Answer 1

[Chunru]

A= [0.5958    0.8909    0.9135
    0.5348    0.0558    0.4093
    0.0265    0.1159    0.8576
    0.0066    0.1568    0.8366
    0.4693    0.2467    0.2841];
B= [0.4251    0.2552    0.8203
    0.3655    0.3306    0.3039
    0.4244    0.4263    0.1493
    0.4422    0.3184    0.2394
    0.0107    0.1467    0.8425];
d = vecnorm(A-B)

d = 1×3

0.7850 0.7824 1.0908

Answer 2

[Rohit Kulkarni]

Hi ,

You can do like this:

A = [1 2;3 4]

A = 2×2

1 2 3 4

B = [4 2;7 4]

B = 2×2

4 2 7 4

Distance1  = sqrt(sum((A - B) .^ 2))

Distance1 = 1×2

5 0