Why am I getting this error when trying to logically compare 2 arrays inside of a struct of the same length

Assigning to 289120 elements using a simple assignment statement is not supported. Consider using

comma-separated list assignment.

Error in SARA_Altitude_processing (line 35)

data(MainRawFilt).(dataNames{k}) = [];

Related documentation

>> data(MainRawFilt).(dataNames{k})

The logical indices contain a true value outside of the array bounds.

>> length(MainRawFilt),length(data.(dataNames{k}))

ans =

806488

ans =

806488

>> size(MainRawFilt),size(data.(dataNames{k}))

ans =

806488 1

ans =

806488 1

This is the sample of the code that is causing error

dataNames = fieldnames(data);

for k = 1:length(dataNames)

dataNm = dataNames(k);

if length(data.(dataNames{k})) == length(data.mainRawAlt)

MainRawFilt = data.mainRawAlt == 8888;

data(MainRawFilt).(dataNames{k}) = [];

MainRawFilt = data.mainRawAlt == 6000;

data(MainRawFilt).(dataNames{k}) = [];

MainRawFilt = (data.mainRawAlt > 5783) & (data.mainRawAlt < 5784);

data(MainRawFilt).(dataNames{k}) = [];

end

end

the variable MainRawFilt is a 806488x1 logical

and i am trying to loop through all of the fields of the struct Data that are the same length as MainRawFilt to filter out certain values across all the fields of that length.

Answer 1

[Jeffrey Clark]

@Bolaji, I believe that with each of the statements data(MainRawFilt).(dataNames{k}) = [] you are reducing the size of data.(dataNames{k}) without correspondingly reducing the size of data.mainRawAlt, so that the size of the next MainRawFilt = statement is not compatible with data.(dataNames{k}). You should change the lines to do all the checks at once:

    if length(data.(dataNames{k})) == length(data.mainRawAlt)
        MainRawFilt = data.mainRawAlt == 8888 ...
                    | data.mainRawAlt == 6000 ...
                    | (data.mainRawAlt > 5783) & (data.mainRawAlt < 5784);
        data(MainRawFilt).(dataNames{k}) = [];
    end

[Bolaji]

data.mainRawAlt is part of the struct that is getting parsed through data.(dataNames{k} so wouldt it still reduce itself?

Answer 2

[Voss]

I think the syntax you want is like this:

data.(dataNames{k})(MainRawFilt) = [];

[Bolaji]

Thank you this seemed to work

[Voss]

You're welcome!

Let me offer some explanation of the difference between how you had it and how it should be:

data(MainRawFilt).(dataNames{k}) = [];
%   ^^^^^^^^^^^^^                       index data with MainRawFilt

data.(dataNames{k})(MainRawFilt) = [];
%                  ^^^^^^^^^^^^^        index data.(dataNames{k}) with MainRawFilt

In the first case, you are asking MATLAB to do something with data(MainRawFilt), i.e., since MainRawFilt is a logical array, data(MainRawFilt) is the elements of data where MainRawFilt is true. But data is (or appears to be) a scalar structure (it's only one structure, not an array of structures), so it doesn't have more than one element - its size doesn't match the size of MainRawFilt, so that's the source of the error.

In the second case, you are asking MATLAB to do something with data.(dataNames{k}), i.e., the field called dataNames{k} in the structure data. The value of this field is an array (of the appropriate length, based on the check that was done previously in the code), so that's the thing you actually want to be doing the logical indexing on, using MainRawFilt.

Let me know if you have any questions. Otherwise, please "Accept This Answer". Thanks!