couldn't understand what's wrong in the function definition.

f = @(t,y) [

((y(2)-a-l.*(abs(cos(y(3)+ pi/4)))).*y(1) + k.*y(1).*cos(y(3)- pi/2)).*(2/tc);

(P - (y(2).*(y(1) + 1))) / tf;

o - (k./tc).*2.* sin(y(3)));

];

getting a problem

"Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for

mismatched delimiters." in this.

Answer 1

[Walter Roberson]

    o - (k./tc).*2.* sin(y(3)));
        1     0         1 2 10!

the digits are the nesting level "after" the character above. You open and then close brackets, leaving zero open brackets. You then open two brackets... and you close three brackets, one more than you opened.

Answer 2

[Chunru]

a =1; P=2; i=3; tf=4; k=5; l=6; tc=7; o=8;
f = @(t,y) [  ( (y(2)-a-l.*(abs(cos(y(3)+ pi/4)) )).*y(1) + k.*y(1).*cos(y(3)- pi/2)).*(2/tc);
               (P - (y(2).*(y(1) + 1))) / tf;
                o - (k./tc).*2.* sin(y(3)) ]      

f = function_handle with value:
    @(t,y)[((y(2)-a-l.*(abs(cos(y(3)+pi/4)))).*y(1)+k.*y(1).*cos(y(3)-pi/2)).*(2/tc);(P-(y(2).*(y(1)+1)))/tf;o-(k./tc).*2.*sin(y(3))]

f(1, [1; 2; 2])

ans = 3×1

-0.0220 -0.5000 6.7010