Get the filename of a loaded file

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Hi,
I have a script that loads a file and do some data plotting. I am loading different files each time I run the script. I manually edit the file name since every time the name is different and comming from an unrelated system.
My script reads the file as follows:
load('\Data_record_file_20220714T121615.mat');
Question:
How can I register the file name in a variable? I want to later use the file name in a string (after trimming it) so that I can automatically include the file name on the plot title.
Thank you.
Fabián

Accepted Answer

Star Strider
Star Strider on 3 Aug 2022
Save the fille name as a string or character array first, then refer to it as any other variable —
filename = '\Data_record_file_20220714T121615.mat';
load(filename);
One option might be to store all the various file names in a cell array or string array, and then just subscript into it —
load_data = load(filecell{k});
where ‘k’ is the desired element of the cell array ‘filecell’ storing the file names.
It is always best to load into a structure output. This avoids problems such as overwriting existing variables, and other potential problems —
load_data = load(filename);
then refer to the fields of ‘load_data’ (or whatever you choose to call it) to recover the various variables.
.
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More Answers (2)

桂生 李
桂生 李 on 3 Aug 2022
try
[FileName, FilePath] = uigetfile;

Walter Roberson
Walter Roberson on 3 Aug 2022
filename = '\Data_record_file_20220714T121615.mat';
load(filename);
[~, basename, ~] = fileparts(filename);
title( "Analysis of " + basename)
Note: we do not recommend that form of load(). We recommend that you assign the output of load() to a variable, which gives you a struct array with one field for each loaded variable; you would then pull fields out of the struct as needed. This is more robust and more efficient, and is needed if you later want to do code generation. There are situations in which MATLAB will ignore variables created by load() that does not have an output variable name.
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