How to limit function output range?

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Jeremy2022
Jeremy2022 on 27 Aug 2022
Answered: Matt J on 28 Aug 2022
Say I wan to create a sine wave between -4 to 4, all other values outside -4 and 4 will be zero.j
Here's the code that I thought it was going to work, but I am getting incorrect dimension, is there another way to achieve what I want to achieve?
t = [-10:0.1:10]
t = 1×201
-10.0000 -9.9000 -9.8000 -9.7000 -9.6000 -9.5000 -9.4000 -9.3000 -9.2000 -9.1000 -9.0000 -8.9000 -8.8000 -8.7000 -8.6000 -8.5000 -8.4000 -8.3000 -8.2000 -8.1000 -8.0000 -7.9000 -7.8000 -7.7000 -7.6000 -7.5000 -7.4000 -7.3000 -7.2000 -7.1000
u1 = @(t) t>=4;
u2 = @(t) t<=4;
u3 = @(t) (u1(t) * u2(t));
x1 = @(t) ((10 * sin(pi*t/4)) * u3(t));
plot(t, x1(t));
Error using *
Incorrect dimensions for matrix multiplication. Check that the number of columns in the first matrix matches the number of rows in the second matrix. To operate on each element of the matrix
individually, use TIMES (.*) for elementwise multiplication.

Error in solution (line 4)
u3 = @(t) (u1(t) * u2(t));

Error in solution (line 5)
x1 = @(t) ((10 * sin(pi*t/4)) * u3(t));
plot(t, x1(-(t+2)/2));

Answers (2)

Matt J
Matt J on 28 Aug 2022
Edited: Matt J on 28 Aug 2022
I would take a simpler approach:
t = [-10:0.1:10];
x1 =10 * sin(pi*t/4).*(abs(t)<=4);
plot(t,x1)

Matt J
Matt J on 28 Aug 2022
Use element-wise multiplication.
u1 = @(t) t>=-4;
u2 = @(t) t<=4;
u3 = @(t) (u1(t) .* u2(t));
x1 = @(t) ((10 .* sin(pi*t/4)) .* u3(t));
fplot(x1,[-10,10])

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