Hi All, My question to all is that .......... I have to add the elements with in the matrix.........

 2     1     2
 1     1     1
 1     1     1

i want to add a(1,2)and a(2,1) and then multiply it with a(1,1) and so on for each element to generate a new matrix........

for a(2,2)..... we will have to do a(2,2) * ( a(1,2)+a(2,3)+a(3,2)+ a(2,1))

this a simple case and i have made the program for 3 by 3 matrix....... but how to generalize it for and n X n Matrix, where n is any number.

thanks for your guidance..........

[Offroad Jeep]

Dear Roger Stafford, Hope you are fine. Can you please kindly check what is the problem with my code why its not generating the hysteresis loop i will be grateful........ waiting for your reply.......

Answer 1

[Roger Stafford]

Let A be an n-by-n matrix.

   B = [zeros(1,n+2);zeros(n,1),A,zeros(n,1);zero(1,n+2)]; % Create a border of all zeros
   B = A.*(B(1:n,2:n+1)+B(3:n+2,2:n+1)+B(2:n+1,1:n)+B(2:n+1,3:n+2)); %Corrected

B will be the desired n-by-n matrix.

[Offroad Jeep]

Dear Roger the first line works by the second is giving error kindly try it for 3 X 3 Matrix,

[Offroad Jeep]

Dear Roger you can see in the attached file what i want to do. just concentrate on the first term Put Jfm = 1, Si = 1, Sj=1........

[Roger Stafford]

I corrected it. It should work now. It had an erroneous comma instead of a plus sign.

[Image Analyst]

Roger, can you explain why this is not the original image times the convolution with a cross-shaped kernel? Even after looking at the more detailed explanation he posted, it looks like it should be. Muhammad, can you give a 5x5 matrix and the 5x5 output matrix as an example?

[Offroad Jeep]

Thanks Roger Stafford for the answer ......... it has worked........Thanks once again...........

Answer 2

[Image Analyst]

It looks like you want to multiply the original image by convolution of it. Try this

kernel = [0, 1, 0; 1, 0, 1; 0, 1, 0]; % Make a "cross" or "+" shape.
sumImage = conv2(originalImage, kernel, 'same');   % Sum and add.
outputImage = originalImage .* sumImage; % Multiply.