use f=@(x) as an argument of a function.m

I have the function

    function [ k ] = New_Raph( f,df,x,tol)

    x_old =x;

    x=1000;

    while abs(x_old-x) > tol

        x_old = x;

        delta=-f(x)/df(x);

        x= x-delta;

    end

    k=x;

    end

And i want to calculate in a new .m file:

    f=@(x) x.^5-0.4475.*x.^4-3.1.*x.^3+3.085.*x.^2-0.962.*x+0.0943;

    df1=@(x) 5.*x.^4-1.79.*x.^3-9.3.*x^2+6.17.*x-0.962;

    New_Raph(@f1,@df1,0,0.1)

What is wrong?

Answer 1

[per isakson]

Replace

    New_Raph(@f1,@df1,0,0.1)

by

    New_Raph(f,df1,0,0.1)

f or f1 - a typo?

&nbsp

Addendum triggered by &nbsp It did not work

Try this example

    >> my_sin = @(x) sin(x)
    my_sin = 
        @(x)sin(x)

    >> arrayfun( my_sin, pi/6*[1,2,3] )
    ans =
        0.5000    0.8660    1.0000

    >> arrayfun( @sin, pi/6*[1,2,3] )
    ans =
        0.5000    0.8660    1.0000

and

    >> arrayfun( @my_sin, pi/6*[1,2,3] )
    Error: "my_sin" was previously used as a variable, conflicting with its use 
    here as the name of a function or command.

[DDD]

It did not work. I tryed making f1.m and df1.m and it solved but in this way it is much cleaner.

[Stephen23]

"It did not work" does not tell us what happened when you tried it: was there an error message, unexpected values or something else?

It should work, according to the information that you have given us. Can you show us your exact code?

Answer 2

[Matt J]

    x= x + delta;