Problem using num2cell!

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BN
BN on 6 Nov 2022
Commented: BN on 6 Nov 2022
Hi, I wanted to split the contents of “A” into separate cells of “C”, where the third dimension of “A” including in each cell. Although num2cell work with no error, the results are wrong!
C = num2cell(A,3);
So far so good, but in the arrays of C, every 1x1x444 cell array contains repetitious values, which is wrong!
C{1,1}
val(:,:,1) =
18.6770
val(:,:,2) =
18.6770
val(:,:,3) =
18.6770
val(:,:,4) =
18.6770
.
.
.
val(:,:,444) =
18.6770
This is the same for other arrays for example C{1,2}, C{2,3}, etc.
I checked the script using another dataset (namely itsok.mat, and it worked properly).
I attached both of my datasets. The A.mat is the file I have a problem with, while the itsok.mat file is the dataset that is ok with the script.
Thank you all.

Accepted Answer

Walter Roberson
Walter Roberson on 6 Nov 2022
A(:,:,2) - A(:,:,1)
is all zero. So is A(:,:,15) - A(:,:,9) and all other possibilities.
nnz(diff(A,[],3))
is zero. Your third dimension of your array is bit-for-bit copies of your first plane.
  1 Comment
BN
BN on 6 Nov 2022
Thank you so much

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