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How to check repeated multiple cell array data for one decimal value?

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Checking the first two set of data in individula cell of 'A' with its 1st decimal value only but could not implement the logical statement with the converted data.
load("A.mat");
count = 0;
for i= 1:3
%B{1,i} = A{1,i}';
C{1,i} = sprintf('%10.1f',A{1,i}); % converted to the values
B{1,i} = reshape(sscanf(sprintf('%10.1f*', A{1,i}),'%f*'),[],1); % converted into single column (1x3)
% if all((B(1,1) == B(i,1)) && (B(2,1)==B(1,i)) % invalid
% count = count+1;
% else
% fprintf("does not matched with any data")
% end
end
  6 Comments
Dyuman Joshi
Dyuman Joshi on 15 Jan 2023
A=load("A.mat").A
A = 1×3 cell array
{2×766 double} {2×766 double} {2×995 double}
for idx=1:numel(A)
%rounding upto 1 point after decimal
B=round(A{idx},1);
%checking if the line is repeated or not
fprintf('Checking for repetition in row1 of A{1,%d}',idx)
row1=any(abs(B(1,2:end)-B(1,1))<1e-1,2)
fprintf('Checking for repetition in row2 of A{1,%d}',idx)
row2=any(abs(B(2,2:end)-B(2,1))<1e-1,2)
%use find() to obtain the indices where the repetition occurs
end
Checking for repetition in row1 of A{1,1}
row1 = logical
1
Checking for repetition in row2 of A{1,1}
row2 = logical
1
Checking for repetition in row1 of A{1,2}
row1 = logical
1
Checking for repetition in row2 of A{1,2}
row2 = logical
1
Checking for repetition in row1 of A{1,3}
row1 = logical
0
Checking for repetition in row2 of A{1,3}
row2 = logical
1

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