Unnest a Matrix of strings

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Brian Morrison
Brian Morrison on 25 Mar 2015
Edited: Andrew Newell on 25 Mar 2015
I have an older version of matlab (R2008a) and I am trying to Unnest an output from a for loop where the out put should be a 3x3 matrix of strings. Where the output currently displayed is:
= {3x1 cell} {3x1 cell} {3x1 cell}
I have tried:
But this returns a matrix where the cells in the third column are still displayed as:
[1x22 char]
[1x21 char]
[1x29 char]
any help would be appreciated thanks

Answers (3)

Andrew Newell
Andrew Newell on 25 Mar 2015
Edited: Andrew Newell on 25 Mar 2015
If I understand what you're trying to do, you can't do it. A 3x3 matrix of strings looks like this:
ans =
If you try something like repmat(ans,[1 3]), you get:
ans =
If you want a string array, you could try
This will give you an array of 9 strings, one per line.
EDIT: Based on the discussion below, you might want to try:
fileID = fopen(your_file_name,'r');
C = textscan(fileID,'%s %s %s\n','Delimiter',',');
EDIT2: Based on further discussion, I think this will do what you want:
fileID = fopen('string_data','r');
C = textscan(fileID,'%s %s %s\n','Delimiter',',','CollectOutput',true);
C = regexprep(C{1},'''','')
The textscan command divides the strings up, ignoring the commas, and collects the result in a cell array C inside of which is an N x 3 cell array (don't you just love MATLAB I/O?). The regexprep command gets rid of stray quotation marks.

Ced on 25 Mar 2015
Edited: Ced on 25 Mar 2015
I'm afraid that this is a bit unavoidable.
L = [M{:}];
would return you a 3x3 cell with the desired strings. If you convert that into a matrix though (e.g. with cell2mat), you run into two problems:
a) [ 'ab','bb','cb' ] is interpreted by matlab as a concatenation of characters, and not three distinct entries of a matrix.
b) if I understand correctly, your entries do not all have the same number of characters. Because matlab interprets each character of a string as a "column" in a matrix, you cannot save strings of different lengths in the same matrix.
Personally, I would go with a 3x3 cell. I don't see a reason not to use cells for non-numerical values.
EDIT: too slow... :)
Andrew Newell
Andrew Newell on 25 Mar 2015
I think I understand what you want now, and my second edit in my own answer will do it.

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Konstantinos Sofos
Konstantinos Sofos on 25 Mar 2015
You could use simple the vertcat
>> M = {{'a','b','c'},{'d','e','f'},{'g','h','I'}}
M =
{1x3 cell} {1x3 cell} {1x3 cell}
>> L = vertcat(M{:})
L =
'a' 'b' 'c'
'd' 'e' 'f'
'g' 'h' 'I'

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