Warning: Error updating FunctionLine. for fplot
3 views (last 30 days)
Show older comments
I am trying to create a function that summed up a bunch of other functions.
y1 = 0;
addi = 0.05;
aoamid = (2*0.6*sqrt(1-((y1)/4)^2)/(pi^2)+0.6/(8*pi))
CLnew = (aoamid+addi)/(2*sqrt(1-((y1)/4)^2)/(pi^2)+1/(8*pi))
m = (CLnew-0.6)/(addi)
aoafinal = aoamid - 0.6/m
N = 25;
Amatrix = zeros(N);
LLTmatrix = zeros(N,1);
A = sym('A', [N 1]);
for i = 1:N
theta = (1/48)*i+11/48;
for j = 1:N
Amatrix(i,j)= sinpi(j*theta)+(1/32)*2*pi*j*sinpi(j*theta)/sinpi(theta);
end
LLTmatrix(i,1) = (1/32)*2*pi*((2*0.6*sqrt(1-((4*cospi(theta))/4)^2)/(pi^2)+0.6/(8*pi))-aoamid);
end
AN = Amatrix\LLTmatrix;
%the really important part
cl = @(y) 0*y;
for i = 1:N
temp = @(y) AN(i,1)*sin(i*acos(y/4));
cl = @(y) cl + temp;
end
Clnew = @(y) 4*8*cl;
figure(2)
fplot(Clnew, [-4 4])
But this is the error I got:
Warning: Error updating FunctionLine.
The following error was reported evaluating the function in FunctionLine update:
Undefined function 'mtimes' for input arguments of type 'function_handle'.
I don't have mtimes in my code. Could you tell me what is going on?
0 Comments
Answers (1)
Star Strider
on 23 Feb 2023
Evaluate all the functions.
Try this —
y1 = 0;
addi = 0.05;
aoamid = (2*0.6*sqrt(1-((y1)/4)^2)/(pi^2)+0.6/(8*pi))
CLnew = (aoamid+addi)/(2*sqrt(1-((y1)/4)^2)/(pi^2)+1/(8*pi))
m = (CLnew-0.6)/(addi)
aoafinal = aoamid - 0.6/m
N = 25;
Amatrix = zeros(N);
LLTmatrix = zeros(N,1);
A = sym('A', [N 1]);
for i = 1:N
theta = (1/48)*i+11/48;
for j = 1:N
Amatrix(i,j)= sinpi(j*theta)+(1/32)*2*pi*j*sinpi(j*theta)/sinpi(theta);
end
LLTmatrix(i,1) = (1/32)*2*pi*((2*0.6*sqrt(1-((4*cospi(theta))/4)^2)/(pi^2)+0.6/(8*pi))-aoamid);
end
AN = Amatrix\LLTmatrix;
%the really important part
cl = @(y) 0*y;
for i = 1:N
temp = @(y) AN(i,1)*sin(i*acos(y/4));
cl = @(y) cl(y) + temp(y); % <— CHANGED
end
Clnew = @(y) 4*8*cl(y); % <— CHANGED
figure(2)
fplot(Clnew, [-4 4])
.
0 Comments
See Also
Categories
Find more on Whos in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!