For Loop Starting at Zero
12 views (last 30 days)
Show older comments
I'd like to run my Theta for loop across the length of X ( 0 to 1) with my stored values of BI
H = 0.1;
I = 200;
Y = 0;
BI = zeros(I,1);
b = pi;
for i = 1:I
b = fzero(@(b)(b*tan(b)-H),b);
BI(i,1) = b;
end
BI(end);
X = linspace(0,1,I);
Theta = zeros(I,1);
for k = 1:length(X)
Theta(k) = ((((1.\BI).*(1-cos(BI))).\(0.5-(1.\(4.*BI)))).*sin(BI.*Y).*(cosh(2.*BI.*(k-1))-tanh(2.*BI).*sinh(2.*BI.*(k-1))));
end
0 Comments
Answers (1)
dpb
on 7 Mar 2023
H = 0.1;
I = 200;
Y = 0;
BI = zeros(I,1);
b = pi;
for i = 1:I
b = fzero(@(b)(b*tan(b)-H),b);
BI(i,1) = b;
end
unique(BI)
shows you're starting guess isn't good enough to do more than find the same root over and over and over...try (for a much smaller sample size)
I=5; BI=zeros(I,1);
for i = 1:I
b = fzero(@(b)(b*tan(b)-H),pi*i);
BI(i,1) = b;
end
unique(BI)
diff(BI)
I don't really know what the last equation is supposed to be, but to evaluate in the loop over k, one presumes you're looking for BI(k) everywhere you have BI and the .\ operators are really supposed to denote division on an element-by-element basis.
Write the equation out longhand so it can be deciphered if you need more help...
2 Comments
dpb
on 7 Mar 2023
I showed the way to write BI(k) in the loop...oh! I ended up deleting it because it was too hard to try to decipher what was really intended, sorry.
for k = 1:length(X)
Theta(k) = ((((1/BI(k)).*(1-cos(BI(k))))/(....etc., ...
end
Too many parentheses for this old man's eyes to be able to count and the online code editor doesn't automagically match them so leave that to younger eyes than mine... <vbg>
But, there's still confusion about what you really want as there's no X in the equation anywhere; what's the point of it?
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!