How do I append my answers in an array, while using loop?
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Good day, please can someone help me with this problem?
In the code below, I want to add the following conditions:
- Solve the equation 10 times using a "for" loop or while function. That is, have a variable L=10, and substrate 1 from it after each iteration. End loop, when L=0.
- Create an array of two column vectors for the x and y values from each iteration, with x=6, and y=5 as the first values of this array. Similar to append.
- Each solution of x and y, will be used as the z and w values for the next iteration.
z = 6;
w = 5;
syms x y
eqn1 = x + y + z + w == 13;
eqn2 = 2*x + 3*y - w == -1;
sol = solve([eqn1, eqn2], [x,y]);
xSol = sol.x
ySol = sol.y
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Accepted Answer
VBBV
on 23 Mar 2023
z = 6;
w = 5;
syms x y
eqn1 = x + y + z + w == 13;
eqn2 = 2*x + 3*y - w == -1;
A = [6 5; zeros(10,2)]; % create matrix with x and y values as
L = 10;
k = 2;
% using while loop
while L > 0
sol = solve([eqn1, eqn2], [x,y]);
xSol = (sol.x);
ySol = (sol.y);
A(k,:) = [double(xSol) double(ySol)]; % use double
Z = double(xSol);
W = double(ySol);
syms z w x y;
eqn1 = x + y + z + w == 13;
eqn2 = 2*x + 3*y - w == -1;
eqn1 = subs(eqn1,[z,w],[Z,W]); % substitute new values for z and w in eqn1
eqn2 = subs(eqn2,[z,w],[Z,W]); % substitute new values for z and w in eqn2
k = k+1;
L = L-1;
end
A % final matrix with appended values
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