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I want to solve this equation for a and b where A and B is a vector data with dimension (1344x1) A=a(B)^b

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Here; A = data1 ; B = data2
y = data1;
Y = log(y);
A = [ones(length(y),1) log(data2)'];
X1 = inv(A'*A);
X2 = A'.*Y;
X = X1*X2;
a = exp(X(1:1,1));
b = X(2,1:1);
this is the method I am using to solve for this equation. But I am not sure this is the right way to solve nonlinear equations. Can someone suggest an alternate way with an example?
Thank you

Accepted Answer

Walter Roberson
Walter Roberson on 12 Apr 2023
p = polyfit(log(B), log(A), 1);
a = exp(p(2));
b = p(1);
This would at least be a good starting point for a search in linear space (it should be close to as good as you can get in log space.)

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