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Why is the code not continuing to the next if statements in my app?

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Can anybody tell me what I could have done wrong by just looking at the code that I have for callback for start analysis button. It is not continuing to other if statement after checking the app.error==1.
I dont understand why ; in my program it is happening but when I run the app, I just get the results for CaCl2_ZnBr2_MgCl2, not the other combinations if I chose them instead..
I am sorry but the program consists of many functions, thats why I cannot attach all of them here..

Answers (1)

Hassaan
Hassaan on 14 Jan 2024
Without seeing the full context of your application, including how the error field is set and modified across different parts of your code, it's challenging to provide a precise solution. However, I can offer some general advice and debugging tips:
  1. Debugging Strategy: One of the best ways to debug such issues is to use MATLAB's debugging tools. You can set breakpoints in your code to see if certain parts of the code are being executed. For example, place a breakpoint at the start of each if app.error==1 block and check if the program hits these breakpoints.
  2. Error Handling: Ensure that the error property of app is being set correctly in all scenarios. If it's not being updated as expected, the condition if app.error == 1 may never be true for subsequent checks.
  3. Variable Scopes and Lifecycle: Understand the lifecycle and scope of the app.error variable. If it's being modified in a way you don't expect, or if it's not being reset between checks, this could cause the behavior you're experiencing.
  4. Function Outputs: Check the functions like Amongst_CaCl2_ZnBr2_MgCl2 and others for how they set app.error. There might be conditions under which app.error does not get set to 1 even though it should.
  5. Conditional Logic: Review the logic of your if-else statements. It's possible that an earlier condition is always true, preventing later conditions from being checked.
  6. Print Statements for Debugging: Temporarily insert disp statements in your code to print out the value of app.error and other relevant information at various points. This can help you understand the program flow and where it might be diverging from your expectations.
  7. Check for Unhandled Conditions: Ensure that there are no scenarios where app.error could be set to a value that you're not handling.
  8. Complexity Reduction: If possible, simplify your code. Complex nested if-else structures are often prone to logical errors. See if the logic can be simplified or broken down into smaller, more manageable functions.
If you are still unable to resolve the issue, consider sharing a minimal, reproducible example of the problem with the MATLAB community or forums, as sometimes issues like these require a deep dive into the specific logic and flow of your application.
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If you find the solution helpful and it resolves your issue, it would be greatly appreciated if you could accept the answer. Also, leaving an upvote and a comment are also wonderful ways to provide feedback.
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  2 Comments
Hassaan
Hassaan on 14 Jan 2024
@Muazma Ali Please refer to this guide:
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If you find the solution helpful and it resolves your issue, it would be greatly appreciated if you could accept the answer. Also, leaving an upvote and a comment are also wonderful ways to provide feedback.
Professional Interests
  • Technical Services and Consulting
  • Embedded Systems | Firmware Developement | Simulations
  • Electrical and Electronics Engineering
Feel free to contact me.

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