Simple For Loop To Find Indices
1 view (last 30 days)
Show older comments
Hello.
I have a question about a simple for loop. I have an original latlon set of about 500x1 unique coordinates. I have a subset of that latlon set in which I would like to find the indices for. So I have created a for loop to try to find it.
indices = zeros(length(subset),1); %create matrix of zeros to fill
for ii=1:length(subset);
indices(ii) = find(original==subset(ii));
end
But I keep getting: Subscripted assignment dimension mismatch. What am I doing wrong? In the end I want a matrix the size of the subset to indicate which indices are correlated to my latlon subset in relation to my original latlon.
Thank you,
Melissa
0 Comments
Accepted Answer
Guillaume
on 20 Apr 2015
Edited: Guillaume
on 20 Apr 2015
The only way you can get this error with the code you've presented is if is find returns strictly less or more than one element, that is either the element of your subset is not found, or it is found more than once (i.e. your original array is not unique).
In any case, the loop is not needed there are set functions already present in matlab to do what you want. In your case, it's simply:
[~, indices] = ismember(subset, original)
0 Comments
More Answers (1)
Hikaru
on 20 Apr 2015
Edited: Hikaru
on 20 Apr 2015
Are your variables stored as double, or cells?
edit: I'm sorry. I made a mistake and I removed the incorrect statement.
2 Comments
Hikaru
on 20 Apr 2015
I tried your code using a smaller sized variables,
original = [60; 40; 100; 120];
subset = [120; 40; 60];
indices = zeros(length(subset),1);
for ii=1:length(subset);
indices(ii) = find(original==subset(ii))
end
and it works okay as long as the values in subset can also be found in the original vector.
I'm not sure why you got that error without looking at the sample matrix, but have you check if there are same values in the original vector?
See Also
Categories
Find more on Logical in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!