How to use bisection method to approximate values?
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Sajith Dharmasena on 22 Apr 2015
Commented: Sajith Dharmasena on 25 Apr 2015
Okay so I have a function that spits out y values for a range of x values. For example I'm numerically integrating the function y = integral( x^2 + 2x + 6) using trapezoidal method from 0 to 2. So for say, x = 0:0.05:2 I have the corresponding y values. But now using this result, I want to find x values for a range of y values. Does anybody know how to write the code for this using the bisection method? Your help will be greatly appreciated :)
Nalini Vishnoi on 24 Apr 2015
Can you provide more information about the problem? As I understand it, if you are integrating over x and it ranges from 0 to 2, that would mean that there is a single unique value of y. The value would not change as long as the limits of the integration are fixed. Could you please clarify the following information:
1. Do the limits of the integral change?
2. How does y depend on x if the limits of integration are constant?
3. Is the relationship one to one meaning one x value correspond to one unique y value and vice versa?
You can check how to implement a general bisection problem in MATLAB here .
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