Solving a system of equations in R2014a

What am I doing wrong?:

being "beta_ex" a known function dependent on 't',

syms t r_ex_trial alpha_ex_trial
u1=-r_ex_trial*cos(alpha_ex_trial);
v1=-sin(beta_ex);
u2=r_ex_trial*sin(alpha_ex_trial);
v2=-cos(beta_ex);
eqns=[u1==v1+10, u2==v2+5];
vars=[r_ex_trial, alpha_ex_trial];
[sol1,sol2]=solve(eqns,vars,'ReturnConditions',true);

Why does this happen?:

Warning: 4 equations in 2 variables.

Somehow it does not sepparate the equations from the variables. (I've already tried in different ways)

Thanks in advance!

Answer 1

[Alan Weiss]

After I played with your system for a couple of minutes I got the following error:

 Error using solve (line 258)
 The number of output arguments must equal the number of independent variables in a
 system plus 2.

So I tried the following:

 [sol1,sol2,sol3,sol4]=solve(eqns,'ReturnConditions',true);

It worked.

This also worked:

 [sol1,sol2,sol3,sol4]=solve(eqns,vars,'ReturnConditions',true);

Alan Weiss

MATLAB mathematical toolbox documentation

[José Sarilho]

yes, that way it should return 4 constants.

I was looking to obtain r_ex_trial and alpha_ex_trial as functions of beta_ex (3 symbolic variables, where beta_ex is known)