Put arrow and its value in a plot
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Hello there,
I want to show a row and its value in a plot. Please find attached the data. My intended plot should be like this:
load('data_ask_MLD')
figure;
plot(PTn,z);
set(gca,'ydir','reverse')
Thank you!
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Answers (3)
Mathieu NOE
about 11 hours ago
hello
this is a simple example , based on the fex submission :
load('data_ask_MLD')
figure;
plot(PTn,z);
set(gca,'ydir','reverse')
% define which row for display
r = 100;
x = PTn(r);
y = z(r);
al = 1; % arrow length (in x direction)
arrow([x-al,y],[x,y]); % Fex : https://fr.mathworks.com/matlabcentral/fileexchange/278-arrow
text(x-4*al, y, ['MLD = ' sprintf('%0.5g', y)])
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Pramil
about 11 hours ago
Edited: Pramil
about 11 hours ago
Hi Adi,
You can use the "text" function available in MATLAB to create plot shown in your image. Here is the documentation link for the same for your reference:
And here is the updated code:
load('data_ask_MLD')
figure;
plot(PTn,z);
set(gca,'ydir','reverse')
[~, idx] = min(abs(z - MLD));
x_value = PTn(idx);
text(x_value, MLD, 'MLD = 24.7\rightarrow ','HorizontalAlignment','right');
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Star Strider
about 7 hours ago
Edited: Star Strider
about 3 hours ago
The 'textarrow' coordinates have to adapt to the data and then correct for the reversed y-axis direction.
Try this —
load('data_ask_MLD')
figure;
plot(PTn,z);
set(gca,'ydir','reverse')
xlabel('PTn')
ylabel('z')
xapf = @(x,pos,xl) pos(3)*(x-min(xl))/diff(xl)+pos(1); % 'x' Annotation Position Function
yapf = @(y,pos,yl) pos(4)*(y-min(yl))/diff(yl)+pos(2); % 'y' Annotation Position Function
xl = xlim;
yl = ylim;
pos = gca().Position;
MLDval = 24.7;
PTnval = interp1(z, PTn, MLDval) % X-Coordinate Value (Derived From Data) Right End Of The Arrow
zval = interp1(PTn, z, PTnval) % Y-Coordinate Value (Derived From Data)
annotation('textarrow', xapf(PTnval+[-2.25 -0.25],pos,xl), 1-yapf([1 1]*zval,pos,yl), String=("MLD = "+MLDval)+" m ", HeadStyle='vback3')
EDIT — (23 Nov 2024 at 12:45)
Changed 'HeadStyle'.
.
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