Number of values between constraints

t=linspace(0,pi,1001); y=floor(100.*sin(t));

Find the number of values of y between 25 and 71, inclusive.

Okay, so it's basically finding the length of the values in between the given range. I can tell that it'll require looping, but I don't know how to set it up. Thank you for any and all help

Answer 1

[Sean de Wolski]

No reason to loop:

n = sum(x>=25&x<=71)

[Daniel]

I need the number of values between 25 and 71.

[Sean de Wolski]

yes, that's what 'n' will be if you run my line of code on a vector x. if x is a matrix, you'll have to call sum once for every dimensions in ndims(x) or reshape(x,[],1);

[Walter Roberson]

or

sum(x(:)>=25 & x(:)<=71)

[Daniel]

Ah, I see. I had to tweak the format of the other equations, but your code was solid. Thank you so much.

Answer 2

[Walter Roberson]

Use the logical indexing techniques you learned from your previous question, and then instead of summing the contents of the array, determine the number of "true" comparisons that resulted (I'm deliberately not saying how to do that; you should be able to build on the previous techniques.)

[Daniel]

Thanks Walter, I've used the "For", and then used an "If" to verify which values fall within the range. What I'm having trouble with is getting the "length" of those values. Is there a way to assemble them in a matrix from the looping process and then simply use "length" on that matrix?