I need to find out the bit rate of following?Whether it is correct way to do it or not? Thanks in advance

Bit rate=(file size*8000)/length of signal;

Bit rate=(4.4922kb*8000)/28.68sec;

and the answer is 1253.05 bits per second but I need to find out bit rate in terms of bits per sample ,how do I calculate it?

Answer 1

[Walter Roberson]

File size in bytes times 8 bits per byte, divide by number of samples, divide by number of channels.

The bits per sample is independent of the sampling frequency.

[PRATIBHA WARKADE]

Can you elaborate it with example,please?If I have no. of channels equal to 2.I have no. of samples equal to 1264896x2,but after resampling I got the value of no. of samples as 574x2.I am confused with it that whether I need to put 1264896 or 574 as no. of samples?Please do guide me?

[Walter Roberson]

http://uk.mathworks.com/matlabcentral/answers/239464-if-i-have-no-of-channels-equal-to-2-i-have-no-of-samples-equal-to-1264896x2-but-after-resampling-i#answer_191303