if bit rate=(File size in bytes X (8 bits/bytes))/(no. of samples x no. of channels).....,whether is it correct method of doing it?thanks in advance...
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file size=1.8047kb,no. of samples=230,no. of channels=2; then bit rate=(1.8047 x 8000)/(230 x 2)=31.38 bits per sample.
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on 13 Sep 2015
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on 20 Aug 2021
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