How can I find matching rows between two matrices and and retrieve a value to be applied to the matched row?

I'm trying to take matrix (A) & search matrix (B) for matching rows (matching columns 1-5) and retrieve the value from (B) column 6 to be added to matrix (A) column 6.

A={1 1 1 1 1 2; 1 1 1 1 2 3; 1 1 1 1 3 1; 1 1 1 1 4 2; 1 1 1 1 5 8;
   1 1 1 1 6 3; 1 1 1 1 7 1; 1 1 1 1 8 0; 1 1 1 1 9 9; 1 1 1 2 0 2};
B={1 1 1 1 2 1; 1 1 1 1 4 1; 1 1 1 1 6 2; 1 1 1 2 0 3; 1 1 1 1 9 3; 
   1 1 1 1 1 0; 1 1 1 1 3 0; 1 1 1 1 5 0; 1 1 1 1 7 4; 1 1 1 1 8 8};

% Find A's match within B's matrix
[~,~,ib] = intersect(A(:, 1:5), B(:, 1:5), 'rows');

% Get Adjustment (Column 6) values from B
adjustment = B(ib, 6);

% Apply Adjustments to B
for z = 1:length(RxPDW)
  A(z,6) = sum(A(z,6),adjustment(z,1));
end

I'm trying get a result of

A={1 1 1 1 1 2; 1 1 1 1 2 4; 1 1 1 1 3 1; 1 1 1 1 4 3; 1 1 1 1 5 9; 1 1 1 1 6 5; 1 1 1 1 7 9; 1 1 1 1 8 13; 1 1 1 1 9 12; 1 1 1 2 0 9}

Answer 1

[dpb]

I don't think your desired result is consistent with your input...

>> [A(:,6) B(ib,6)]
ans =
   2     0
   3     1
   1     0
   2     1
   8     0
   3     2
   1     4
   0     8
   9     3
   2     3
>>

I get instead

>> A(ia,6)=A(ia,6)+B(ib,6)
A =
   1     1     1     1     1     2
   1     1     1     1     2     4
   1     1     1     1     3     1
   1     1     1     1     4     3
   1     1     1     1     5     8
   1     1     1     1     6     5
   1     1     1     1     7     5
   1     1     1     1     8     8
   1     1     1     1     9    12
   1     1     1     2     0     5
>>

which seems consistent if I look at the results from intersect which also seems consistent with the input by eye...

[Patrick Conaway]

Thanks dpb! fairly new to Matlab, that worked perfectly & is cleaner than my for loop (now to try it on my 1.5million line data sample)

& output was slightly off, i was hand jamming an example while wife was prepping dinner...

THANKS AGAIN!!!