How to use cumsum + interp1q on reset values.

[ 0 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 1 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 ]

cumsum with reset '3' value and delete repeated values

[ 0 0 0 0 1 0 0 2 0 0 3 0 0 0 1 0 2 0 3 0 0 1 0 0 2 0 0 3 0 0 0 1]

interp1q to fill in 0s

[ 0 0.25 0.5 0.75 1 1.33 1.67 2 2.33 2.67 3 0.33 0.67 1 1.33 1.67 2 2.33 2.67 3 0 0.25 0.5 0.75 1 ]

I tried several ways.., but I can't find a way.

[Hyowon Lee]

is there any function to fill in the 0s? (because interp1q could not be used for this)

Answer 1

[Walter Roberson]

A = [ 0 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 1 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 ];
C = mod((1:sum(A)) - 1, 3) + 1;   cumsum with reset '3' value and delete repeated values
newA = 0 * A;
newA( logical(A) ) = C;

and now do your interpolation. However, you cannot use interp1() because interp1() would use the 3's as the basis of interpolation rather than resetting to 0.