sir I found sum of eigen values of a square matrix. Now I want to find the number of components which cover up to 0.95(95%). My part of prgramme is given in body

sumlamda=0;
for i=1:p
    sumlamda = sumlamda+lamda(i);  
end
sum=sumlamda
ccomp=0;

s =lamda(p)/sum;
for i =(p-1):1
  if s <=0.95
    ccomp = ccomp+1;
  end
  s=(lamda(i)+lamda(i+1))/sum ;
end 
ccomp

Answer 1

[Thorsten]

 E = sort(lambda, 'descend');
 N = nnz(cumsum(E/sum(E)) <= 0.95)