How to find unique value in serial order??

I have a matrix

 p = [90 90 -45 0 0 45 45 0 -45];

i want unique values in serial order from right side

 q = [90 -45 0 45 0 -45];

Means from right side first value is -45, second is 0, third is 45...etc

I want repeated unique number according to serial from RHS.

Means sort repeated values.

Answer 1

[the cyclist]

Does this do what you want?

p = [90 90 -45 0 0 45 45 0 -45];
idx = [true diff(p)~=0];
q = p(idx);

If not, can you give another example or two that illustrates the rule?

[Triveni]

The Cyclist Sir,

I have inserted an image. Here every p(9) values are interchange/swap by q(length(q-1)); and store & store temporary copy to c(:,:,1). then p(9) or c(1,9,1) interchange/swap by q(length(q-2)); and save temporary copy to c(:,:,2). then p(9) or c(1,9,2) interchange/swap by q(length(q-3)); and save temporary copy to c(:,:,3). and so on. can you make a program for me. I'll be very thankful to you.

[the cyclist]

Is this a homework problem? If so, can you show some work that you tried yourself?

You can see my comment on Walter's solution, to see the way to get q.

Answer 2

[Walter Roberson]

q = p;
q(1+find(q(1:end-1)==q(2:end))) = [];

[Triveni]

Thanks walter Sir, Actually i seen late...please solve my another query....can i find positions of matrix q according to p from RHS. means q= [90 -45 0 45 0 -45] & layer location according to p is [2 3 5 7 8 9]

[the cyclist]

p = [90 90 -45 0 0 45 45 0 -45];

pLR = fliplr(p);
idxLR = [true diff(pLR)~=0];
locationsLR = find(fliplr(idxLR))