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How to extract continued values from for cycle

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I've a for cycle that processed thousand files, I don't succeed to take for each for cycle the values generated and store it into a table (or cell or matrix..).
Example:
for cycle return: 1 cycle --> t1 and t2
2 cycle --> t3 and t4
.... n cycle --> tn1 and tn2
creata a table (or something like that to store and give accesible the data) with two separates columns like this:
t1 t2
t3 t4
...
tn1 tn2
Thanks in advance
Stefano

Answers (1)

Brattv
Brattv on 12 Feb 2016
Hi, I am not sure if t1 and t2 are scalars or vectors/matrices, but is this what you are looking for?
% number of files
n = 1000;
% Making a empty matrix
storeValues = [];
for i=1:n
% Making random numbers as example
t1 = rand(1);
t2 = rand(1);
% Storing values in matrix
storeValues(i,:) = [t1 t2];
end
% Printing vector in command window
storeValues
  3 Comments
Stephen23
Stephen23 on 12 Feb 2016
Edited: Stephen23 on 12 Feb 2016
Have you read my answer ?
It might resolve a lots of your code problems.
PS: you might also start to learn why it is a bad idea to ask many questions on the same topic: because you cannot keep track of what information people have given you.
Brattv
Brattv on 12 Feb 2016
You need to keep track of your variable types. Use a cell to store the date data that datestr returns. You should also remove the for loop inside the loop.
% Making a empty matrix
storeValues = cell(1,2);
for k =1:3 %numel(D)
fid = fopen(fullfile(D(k).name), 'rt');
filename = D(k).name ;
a=filename(11:end);
b=regexp(a,'__','split');
out1=cellfun(@(x) datestr(datenum(x(1:10),'yyyy_mm_dd'),'yyyy/mm/dd'),b,'un',0);
out2=cellfun(@(x) datestr(datenum(x(12:end),'HH_MM'),'HH:MM'),b,'un',0);
out=[out1' out2'];
prova = [out{1,1}, ' ', out{1,2}];
prova2 = [out{2,1}, ' ', out{2,2}];
format shortg;
t1 = datevec(prova,'yyyy/mm/dd HH:MM');
t2 = datevec(prova2,'yyyy/mm/dd HH:MM');
% Storing values in matrix
storeValues(i,:) = [cellstr(t1), cellstr(t2)];
end
% Printing vector in command window
storeValues

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