if i have matrix how to do this operation on it ??
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and if i have this matrix A , a , b
A = [ 1 3
1 1
2 2
2 0 ]
a = [ 4 which mean how there is one in A
2
4
2 ]
b = [ 2 which mean how there is element in A
2
2
1 ]
after that i want to do this
F = zeros(4,5);
for k=1:n
if m == ( a(k) + ( b(k) - 1 ))
IF the condition is true then goes to the same k row in A and put it in F the ones like that
After apply this loop then in first row and in third row the condition is true
F = [ 1 0 1 1 1
0 0 0 0 0
1 1 0 1 1
0 0 0 0 0 ]
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Accepted Answer
dpb
on 29 Apr 2016
Edited: dpb
on 29 Apr 2016
>> m=5; n=length(A); % define sizes
>> F=zeros(n,m); % preallocate output
>> ix=find(sum(A,2)+sum(A~=0,2)-1==m); % rows contain some ones
>> F(ix,:)=1; % start with all '1'
>> F(sub2ind(size(F),ix,A(ix,1)+1))=0 % zero the locations not '1'
F =
1 0 1 1 1
0 0 0 0 0
1 1 0 1 1
0 0 0 0 0
>>
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