how to find index of nx2 matrix by comparing elements

Hi, giving a matrix of size nx2

A=[ 222,186;
    222,187;
    223,187]

giving 2 values i= 222 and j=187 i want to find the index the row that contain i on the first column and j on the seond wich is 2 here i want something like

i thought to do somthing like this

for k=1:size(A,1)
      test=find(A(k,1)==i && A(k,2)==j)
      if (test==1)
           ind=k;
           break;
      end
 end

i need only the first index like i did here but i want to avoid the loop.

Thanks

Answer 1

[Jos (10584)]

A=[ 222,186;
    222,187;
    223,187]
i = 222
j = 187

% two alternatives
r1 = find(A(:,1)==i & A(:,2)==j))
[tf,r2] = ismember(A,[i j],'rows')

[sbei arafet]

thanks