Convert the Mathematica expression to matlab

Hello I want to convert the following lines to matlab.But I am unable to do it with matlab to function.Please help..

x[i_]:=x[i]=x[i-1]+h f1[t[i-1],x[i-1],y[i-1],z[i-1]]+1/2 h2 (f1(1,0,0,0)[t[i-1],x[i-1],y[i-1],z[i-1]]+f1(0,1,0,0)[t[i-1],x[i-1],y[i-1],z[i-1]] f1[t[i-1],x[i-1],y[i-1],z[i-1]]+f1(0,0,1,0)[t[i-1],x[i-1],y[i-1],z[i-1]] f2[t[i-1],x[i-1],y[i-1],z[i-1]]+f1(0,0,0,1)[t[i-1],x[i-1],y[i-1],z[i-1]] f3[t[i-1],x[i-1],y[i-1],z[i-1]])

This is implementation of Taylor series.

Answer 1

[Thomas]

MAtlab has inbuilt function for Taylor series

doc taylor

http://www.mathworks.com/help/toolbox/symbolic/taylor.html

[LOKESH]

but here it is taylor method of order 3 for 3 different equations in one loop only.

Can i do that with inbuilt function.

[Walter Roberson]

for K = 1 : length(Equations)

tans(K) = taylor(Equations(K), 3, Variables(K));

end

Looks like a single loop to me.