First paragraph of
ends by : If Y is delayed with respect to X, D is positive. If Y is advanced with respect to X, D is negative.
Therefore your sequence pd is advanced by 2 samples with respect to hd.
The delay (in time) is equal to the number of samples multiplied by the sampling period.
(By the way, the unit of measurement of a sampling rate is "samples/seconds" or "Hz" and not "seconds" ; therefore, did you give the sampling "rate" or the sampling "period" ?)