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kindly can anybody suggest and help me to correct my code ?

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s=[0 1];
Let
k{1,2}{1,1}=01010001
k{1,2}{1,2}=11010101
k{1,2}{1,3}=01010001
k{1,2}{1,4}=11010001
k{1,2}{1,5}=00010001 (continued upto {1,2}{1,7})
%
if (strcmp(k{1,2}{1,1}, '00000001') || (strcmp(k{1,2}{1,1}, '10000000')))&& s(1)==0
p{i,j}='00000001';
%
elseif (strcmp(k{1,2}{1,1}, '00000001') || (strcmp(k{1,2}{1,1}, '10000000')))&& s(1)==1
p{i,j}='10000000';
%
elseif (strcmp(k{1,2}{1,2}, '0000001') || (strcmp(k{1,2}{1,2}, '1000000')))&& s(1)==0
p{i,j}='0000001';
%
elseif (strcmp(k{1,2}{1,2}, '0000001') || (strcmp(k{1,2}{1,2}, '1000000')))&& s(1)==1
p{i,j}='1000000';
%
elseif (strcmp(k{1,2}{1,3}, '000001') || (strcmp(k{1,2}{1,3}, '100000')))&& s(1)==0
p{i,j}='000001';
%
elseif (strcmp(k{1,2}{1,3}, '000001') || (strcmp(k{1,2}{1,3}, '100000')))&& s(1)==1
p{i,j}='100000';
%
elseif (strcmp(k{1,2}{1,4}, '00001') || (strcmp(k{1,2}{1,4}, '10000')))&& s(1)==0
p{i,j}='00001';
%
elseif (strcmp(k{1,2}{1,4}, '00001') || (strcmp(k{1,2}{1,4}, '10000')))&& s(1)==1
p{i,j}='10000';
%
elseif (strcmp(k{1,2}{1,5}, '0001') || (strcmp(k{1,2}{1,5}, '1000')))&& s(1)==0
p{i,j}='0001';
%
elseif (strcmp(k{1,2}{1,5}, '0001') || (strcmp(k{1,2}{1,5}, '1000')))&& s(1)==1
p{i,j}='1000';
it is running fine as expected but what i want is suppose at the condition
>> elseif (strcmp(k{1,2}{1,5}, '0001') || (strcmp(k{1,2}{1,5}, '1000')))&& s(1)==1
is met.
i want p{i,j}= '00011000' i.e it should contain the value '1000' and its before original values also. similarly for other cases also. kindly can anybody suggest and help me.
  2 Comments
Steven Lord
Steven Lord on 10 Nov 2016
Can you explain in words (NO CODE) what you're trying to do? What are the inputs to this procedure and what should the procedure output?
aditya kumar sahu
aditya kumar sahu on 10 Nov 2016
Edited: Walter Roberson on 10 Nov 2016
First of all there are some binary numbers let, x=01100001,...etc. I want to compare those with some conditions like
if x==00000001 or 10000000 and y==0
then x=00000001
elseif x==00000001 or 10000000 and y==1
then x=10000000
elseif .......(continued until it matches)
so finally for x==000001 or 100000 and (s=0/1) it will match..
at this point i need the value of x should be 011000001 ..
Thats it,...i hope now you can get..

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Answers (1)

John D'Errico
John D'Errico on 10 Nov 2016
You may think that this produces a binary number.
k{1,2}{1,1}=01010001
It does not. It stores a double precision number: 1010001. Note there is not even a leading zero.
You cannot then do a comparison like this:
strcmp(k{1,2}{1,1}, '00000001')
And expect anything to work properly.
You need to read about data types in MATLAB. Learn the difference between strings and numeric types.

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