Koch Square Problem : A(I): index out of bounds; value 4 out of bound 3
3 views (last 30 days)
Show older comments
Can someone please fix my error?
0 Comments
Answers (1)
Walter Roberson
on 14 Nov 2016
You use newpointsx(4) and newpointsy(4) before you have assigned anything to those locations. Two lines further on you use the (5) indices too.
5 Comments
Walter Roberson
on 14 Nov 2016
Your code has
v=[newpointsx(4);newpointsy(4)]-[newpointsx(2);newpointsy(2)]
vprime = R*v
f=[newpointsx(5);newpointsy(5)]-[newpointsx(3);newpointsy(3)]
fprime = R*f
newpointsx(4) = vprime(1)+newpointsx(2) %Point D
newpointsy(4) = vprime(2)+newpointsy(2)
newpointsx(5) = fprime(1)+newpointsx(3) %Point F
newpointsy(5) = fprime(2)+newpointsy(3)
Notice that you use newpointsx(4) and newpointsy(4) in calculating v, but you do not assign any value to newpointsx(4) or newpointsy(4) until 5 lines later in the code.
You need to assign values to newpointsx(4), newpointsx(5), newpointsy(4), newpointsy(5) before you can use them in calculations.
KSSV
on 15 Nov 2016
@ Walter Roberson, I apologize, I have not seen all this discussion and in hurry closed the question. I shall be careful next time.
See Also
Categories
Find more on Octave in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!