error in solving cell array multiplication

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summyia qamar
summyia qamar on 13 Jan 2017
Edited: James Tursa on 13 Jan 2017
how can I do the column multiplication of each cell array with a vector? I have a A= 2 4 2 4 2 3 and a cell array cell with 6x7 double.. I want to multiply row(1) of 6x7 double with A(1), row(2) with A(2)and so on.
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summyia qamar
summyia qamar on 13 Jan 2017
no_of_machines=7;
no_of_cells=3;
No_of_Parts = 6;
demand_period=26;
Demand=[600;550;500;520;620;500];
Capacity_ofmachines=[960 960 960 960 960 960 960];
OP1=[5 0 0 5 0 6 4;5 7 0 0 4 0 6];
OP2=[0 5 4 5 0 0 6;7 0 4 0 5 7 0];
OP3=[5 0 0 4 8 0 0;0 5 7 0 0 0 6];
OP4=[5 0 0 0 7 0 6;0 5 0 6 0 7 0];
OP5=[5 4 0 0 0 6 0;6 7 0 0 5 0 8];
OP6=[0 5 0 0 0 7 6;5 6 0 7 0 4 0];
for n=1:6
Daily_demand(n)=Demand(n)/demand_period;
end
% All combinations of routes for parts
P = [OP1;OP2;OP3;OP4;OP5;OP6];
z = [size(OP1,1) size(OP2,1) size(OP3,1) size(OP4,1) size(OP5,1) size(OP6,1)];
c = [0 cumsum(z(1:end-1))];
a = allcomb(1:z(1),1:z(2),1:z(3),1:z(4),1:z(5),1:z(6));
n = size(a,1);
all_comb_of_routes = cell(1,n);
for k=1:n
for n=1:No_of_Parts
all_comb_of_routes{k} = P(c+a(k,:),:);
end
end
after this step of generating 1x64 cell arrays I want to run loop over each cell of 6X7 size in which the daily_demand 1st element multiply by 1st row of cell, 2nd element of daily_demand multiply by 2nd row and so on for all cell arrays

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Accepted Answer

James Tursa
James Tursa on 13 Jan 2017
Edited: James Tursa on 13 Jan 2017
result = cellfun(@(X)bsxfun(@times,Daily_demand(:),X),all_comb_of_routes,'uni',false);
btw, you can replace this code:
for n=1:6
Daily_demand(n)=Demand(n)/demand_period;
end
with simply this:
Daily_demand = Demand / demand_period;
And what is the point of the "for n=1:No_of_Parts" loop? You are using the same variable n here which is used for the outer loop. I don't think you really want to do that.

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