how to apply column wise operation on each matrix in cell

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I want to apply a condition of cell array allCells_array which contains matrices of 7x3 size.I want to check that if sum of each column of matrix is less than equal to 3 then do multiplication else go to next matrix in cell how to define this function and where to put END of IF in the given code?
for m=1:c2
for n=1:numel(allCells_array)
*here to put IF STATEMENT*
movement=(all_comb_of_routes{m})*allCells_array{n};
movement=movement>0;
total_movement=sum((sum(movement,2))-1);
count=count+1;
total_all(count)=total_movement;
end
end
complete code:
%%///FOR ALL COMBINATIONS OF ROUTES(64X1806)
clear all;
clc;
tic;
no_of_machines=7;
no_of_cells=3;
No_of_Parts = 6;
%/// STEP 1: MAKING 64 COMBINATIONS OF ALL PARTS ROUTING
P1=[1 0 0 1 0 1 1;1 1 0 0 1 0 1];% AVAILABLE ROUTES FOR PART 1
P2=[0 1 1 1 0 0 1;1 0 1 0 1 1 0];% AVAILABLE ROUTES FOR PART
P3=[1 0 0 1 1 0 0;0 1 1 0 0 0 1];% //
P4=[1 0 0 0 1 0 1;0 1 0 1 0 1 0];%//
P5=[1 1 0 0 0 1 0;1 1 0 0 1 0 1];%//
P6=[0 1 0 0 0 1 1;1 1 0 1 0 1 0];%//
% GENERATING ALL POSSIBLE COMBINATIONS OF 12 ROUTES
P = [P1;P2;P3;P4;P5;P6];
z = [size(P1,1) size(P2,1) size(P3,1) size(P4,1) size(P5,1) size(P6,1)];
c = [0 cumsum(z(1:end-1))];
a = allcomb(1:z(1),1:z(2),1:z(3),1:z(4),1:z(5),1:z(6));
n = size(a,1);
all_comb_of_routes = cell(1,n);
for k=1:n
all_comb_of_routes{k} = P(c+a(k,:),:);
end
%//STEP 2:GENERATING ALL CELLS COMBINATIONS FOR MACHINES
CELL = zeros(no_of_cells^no_of_machines,no_of_machines);
t = 0;
for k = 0:(no_of_cells^no_of_machines)-1 %k=(2187-1=2186)
s = dec2base(k,no_of_cells,no_of_machines);
if length(unique(s))==no_of_cells
t = t+1;
CELL(t,:) = s-'0'+1;
end
end
CELL = CELL(1:t,:);
combination_array=num2cell(CELL,2);% all possible combinations
%//GENERATING MACHINE CELL MATRICES FROM ABOVE 1806 COMBINATIONS
[r1,c1]=size(combination_array);
for l=1:r1 %(l)= 1806 (no.of combinations of machines and cells)
R=1:numel(combination_array{l});
Z = zeros(R(end),max(combination_array{l}));
Z(sub2ind(size(Z),R,combination_array{l})) = 1;
allCells_array{l}=Z; % machine cell matrix array of all combinations
end
[r2,c2]=size(all_comb_of_routes);
count=0;
for m=1:c2
for n=1:numel(allCells_array)
movement=(all_comb_of_routes{m})*allCells_array{n};
movement=movement>0;
total_movement=sum((sum(movement,2))-1);
count=count+1;
total_all(count)=total_movement;
end
end
minValue=min(total_all)
[all_comb_of_routes(m) combination_array(n) allCells_array(n) minValue]
toc;

Accepted Answer

Image Analyst
Image Analyst on 14 Jan 2017
Not quite sure what the loop over n is for, but from your words, it sounds like you want to do something like this:
for m = 1 : length(all_comb_of_routes)
% Extract the 7-by-3 matrix from inside the cell
thisCellContents = all_comb_of_routes{m}
% Sum if vertically.
columnSums = sum(thisCellContents, 1);
% See if each column sums to less than 3
% and multiply by some number.
if all(columnSums < 3)
% All 3 sums are less than 3.
thisCellContents = thisCellContents * allCells_array{n};
% Put new result back into the cell
all_comb_of_routes{m} = thisCellContents;
else
% At least one of the columns sums to 3 or more.
% Nothing to do, just skip to the end of the loop
continue;
end
end
  2 Comments
Image Analyst
Image Analyst on 14 Jan 2017
For #1, I did that:
% Extract the 7-by-3 matrix from inside the cell
thisCellContents = all_comb_of_routes{m}
That will be a 7x3 numerical array, not a cell anymore.
For #2, you need to use the all() function on the column sums, as I showed in my example.

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