# How to print size of array?

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John on 11 Jul 2017
Answered: Steven Lord on 11 Jul 2017
The array size need to monitor. It's simple and effective with size(x) but no name or location. It would be nice to print if out this way:
fprintf(' size(xyz) at location 123 is [%d %d %d] \n',size(xyz));
because size(xyz) is "unknown" and how to write [%d %d %d] to print size(xyz) in one row?

Steven Lord on 11 Jul 2017
>> A = rand(2, 3, 1, 4);
>> fprintf('size(A) is %s\n', mat2str(size(A)))
or
>> A = rand(2, 3, 1, 4);
>> fprintf('size(A) is [%s]\n', int2str(size(A)))
Note that the spacing between the elements of the size may be a little different for those two approaches.

Geoff Hayes on 11 Jul 2017
John - is xyz your 3D array? If so, then try
fprintf(' size(xyz) at location 123 is [%d %d %d] \n',size(xyz, 1), size(xyz, 2), size(xyz, 3));
##### 2 CommentsShow NoneHide None
John on 11 Jul 2017
Dimension is unknown. That's the problem!
Geoff Hayes on 11 Jul 2017
then consider using ndims with
xyz = randi(255,12,13,14);
fprintf('size(xyz) at location 123 is [');
for k=1:ndims(xyz);
fprintf(' %d',size(xyz, k));
end
fprintf(']\n');
or
fprintf('size(xyz) [');
fprintf('%d ',size(xyz)');
fprintf(']\n');
Or do you have a requirement that stats that you can only print this in one line?

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