NRZ-4 and NRZ-8

How can I do a level 4 and level 8 nrz?

i have a terrible teacher and he ask for it.

[Rick Rosson]

Please provide more details. What are you trying to do? Please be as specific as possible.

[Acosta]

i need to do a mask level 4 with following binary: 1011001111 and then do a mask level 8 too

[Rick Rosson]

What is a "mask level 4"? What do you mean when you say "do"?

[Acosta]

http://en.wikipedia.org/wiki/Amplitude-shift_keying

mask it's multilevel amplitude-shift keying and what I need is a level 4 and level 8 ask

[Acosta]

http://www.slideshare.net/mahinthjoe/lecture-4-1580897

Answer 1

[Rick Rosson]

   >> doc bin2dec
   >> doc stairs

[Acosta]

Is that enough? I just dont understand how 2 do

[Rick Rosson]

Hi Acosta, I am not going to do your homework assignment for you. If you want some help, you need to make an effort to figure it out for yourself. I have given you enough to get started. Please let me know what you have tried on your own, and what _specific_ questions you have.

Answer 2

[Rick Rosson]

Here is another hint:

Suppose you have a series of randomly generated symbols drawn from the set of integers { 0, 1, 2, 3 }, and you would like to map them to the integers { -3, -1, +1, and +3 }, what mathematical formula could you use to compute this mapping?

HTH.

Rick

[Acosta]

my teacher ask us to do the mask with those binary numbers using each char as 1 number. i can't understand how to do it beacuse he only teaches a nrz wave 1 level and this is 4 levels and still using 0 and 1.

[Rick Rosson]

You did not answer the question that I asked. Please think about it.

Answer 3

[Rick Rosson]

You need to convert numbers from a binary representation (base 2) to a decimal representation (base 10). That is why I suggested looking at the bin2dec function.

If you break up the binary string into blocks of 2 bits each, you can use the bin2dec function to convert them to integer-valued numbers, each of which is an element of the set { 0 1 2 3 }. For example:

   b = '10';
   x = bin2dec(b);
   disp(x)

will return the value of x as 2.

Likewise, if you break the binary string into blocks of three bits each, you will end up with integers in the set 0 ... 7 inclusively.

Answer 4

[Rick Rosson]

Another function that may help is reshape.