Define a function for a system using Symbolic Math Toolbox

I want just to define a function y(t).It is the output of my system and I want to use it in a controller as
y(t),y(t+1)
or so and do a Z transformation.
I do not want to define it as:
y=inline('something'), only y(t)
with undefined content.

Answers (5)

For the symbolic toolbox, you probably should use explicit sym calls, as in the following:
>> syms t z
>> evalin(symengine, 'transform::ztrans::addpattern(y(t), t, z, Y(z))')
>> ztrans(sym('y(t+1)'), t, z)
ans =
z*Y(z) - z*y(0)

2 Comments

Are you sure that ans is correct?
Y(z) = sum(y(k)/z^k, k=0..infinity)
z*Y(z) = z*sum(y(k)/z^k, k=0..infinity)
= sum(y(k)/z^(k-1), k=0..infinity)
= sum(y(k+1)/z^k, k=-1..infinity)
= sum(y(k+1)/z^k, k=0..infinity) + z*y(0)
Yes, I think the answer is correct.

Sign in to comment.

What use could an undefined function be? If you want your function to return nothing, then:
y = @(t) [];
would do the trick. Then from the command line:
>> y(5)
ans =
[]
>> y(2:6)
ans =
[]

1 Comment

I have an equation with a lot of calculations with y(t),y(t+1),u(t),u(t+1)
I want to be able to do a Z transformation. eg Z(y(t))=Y(z) and Z(y(t+1)=zY(z))

Sign in to comment.

You would need the Symbolic Toolkit to do this, and you would have to do the transforms using the toolkit facilities, as most Matlab routines do not know how to work with symbolic variables.
syms z t
%funt='1'; %step
%funt='t'; %ramp
funt='t+1'; %shifted ramp
%funt='t^2'; %parabole
fz=@(x) ztrans(sym(x), t, z);
Flaplace=laplace(sym(funt))
ZTranform=fz(funt)
ZTranformSimplified=simplify(fz(funt))
In a function, I didn't called it just y to avoid problems with variables having the same name of files, but you can call it y and do y('t+1') instead of convCSZ('t+1'), calling it like this [ZTranform Flaplace]=convCSZ('t+1') will also give of the laplace transform :) , [ZTranform Flaplace ZTranformSimplified]=convCSZ('t+1') gives also the simplified version of the z transform :)
function [ZTranform Flaplace ZTranformSimplified]=convCSZ(funt)
syms t z
%funt='1'; %step
%funt='t'; %ramp
%funt='t+1'; %shifted ramp
%funt='t^2'; %parabole
%y=inline(funt)
fz=@(x) ztrans(sym(x), t, z);
Flaplace=laplace(sym(funt));
ZTranform=fz(funt);
ZTranformSimplified=simplify(fz(funt));

Categories

Find more on Mathematics in Help Center and File Exchange

Asked:

on 24 Jan 2011

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!